Question

C++ , Write an iterative routine that will have 2 queues. Loop for 100 times and in the loop roll two die and place the first result into the queue1 and second into queue2. Then dequeue the rolls one at a time from each, printing each pair, and count how many times two rolls either add up to 7 or are doubles (i.e. same value). After the queues are empty, print out the number of 7s and doubles.

Assume srand has already been done.

Answer 1

we will use rand() function here to generate random numbers between range(1 to 6) which is dies range.

1+ rand()%6 (rand()%6 generates random number in range 0 to 5 we added 1 to make range 1 to 6)

first we iterate 100 times and inserted values in queue q1 and q2;

Then we popped out elements from queue and counted pair with sum 7 or pair that doubles(both value same).

following is the full code with comments.

#include<bits/stdc++.h>
using namespace std;
int main()
{
    queue<int> q1,q2;//declaring 2 queues
     srand(time(0));//in question given that it is done before
   for(int i=1;i<=100;i++) //iterating 100 times
   {
       //rand() generates raandom number we used %6 to generate random number between  0 to 5 and added one to get number in die's range(1 to 6)
       int value_die1 = 1+(rand()%6);
       int value_die2 = 1+(rand()%6);
       q1.push(value_die1);
       q2.push(value_die2);
   }
   int ans=0;//will tel number of apir which adds up to 7 or doubles
   while(!q1.empty())//as size of both q1 and q2 same  run  lopp til any of them is no empty; 
   {
        int value1 = q1.front();
        q1.pop();
        int value2 = q2.front();
        q2.pop();
        if(value1==value2)  //both number  at dies are same(doubles) 
        ans++;
        if((value1+value2)==7)
        ans++;
   } 
   cout<<ans;
}