In: Statistics and Probability
given a random sample of 50 measurements of acid levels in the water on one day recorded a sample mean of 210 with a standard deviation of 55. Create a 95% confidence interval for the parameter.
Solution :
Given that,
Point estimate = sample mean = = 210
Population standard deviation = = 55
Sample size n =50
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z / 2 = Z0.025 = 1.96 ( Using z table )
Margin of error = E = Z/2 * (
/n)
= 1.96 * (55 / 50 )
= 15.2
At 95% confidence interval
is,
- E < < + E
210- 15.2 <
< 210+ 15.2
194.8 <
<225.2