Question
In: Statistics and Probability
Q4.(15) One random sample of the hours of one type of user watch TV per day...
Q4.(15) One random sample of the hours of one type of user watch TV per day was recorded: 2.9, 3.5, 3, 3.2, 3.3, 3.5, 3.3, 3, 3.5.
1.(5) Apply the backward empirical rule to check normality of the data, and conclude if any evidence of non-normality.
2.(5) Assume that the underlying population is normal. Find a two-sided 99% confidence interval for the the true population average hours
3.(5) Assume that population variance σ2=0.09σ2=0.09 and the bound on the error of estimation of 99% confident interval to be 0.2. Find the minimum sample size nn.
Solutions
orchestra answered 1 year agoRelated Solutions
One random sample of the hours of one type of user watch TV per day was...
One random sample of the hours of one type of user watch TV per
day was recorded: 2.9, 3.5, 3, 3.2, 3.3, 3.5, 3.3, 3, 3.5.
1. Apply the backward empirical rule to check normality of the
data, and conclude if any evidence of non-normality.
2. Assume that the underlying population is normal. Find a
two-sided 99% confidence interval for the the true population
average hours.
3. Assume that population variance ?2=0.09σ2=0.09 and the bound
on the error of estimation...
Q4.(15) One random sample of the height of one type of tree was recorded. 7, 9...
Q4.(15) One random sample of the height of one type of tree was
recorded.
7, 9 ,10, 7 ,12 ,10, 8, 13 ,15, 9
1.(5) Apply the backward empirical rule to check normality of the
data, and conclude if any evidence of non-normality.
2.(5) Assume the height of the tree is normal, calculate the 99%
two-sided confidence interval for the true population average
height.
3.(5) Assume that we know the population variance σ^2=9,
and we request the bound on the...
Q4.(15) One random sample of the height of one type of tree was recorded. 7, 9...
Q4.(15) One random sample of the height of one type of tree was
recorded. 7, 9 ,10, 7 ,12 ,10, 8, 13 ,15, 9 1.(5) Apply the
backward empirical rule to check normality of the data, and
conclude if any evidence of non-normality. 2) Assume the height of
the tree is normal, calculate the 99% two-sided confidence interval
for the true population average height. 3.(5) Assume that we know
the population variance σ2=9, and we request the bound on the...
A researcher collected data on the hours of TV watched per day from a sample of...
A researcher collected data on the hours of TV watched
per day from a sample of five people of different ages. Here are
the results:
i
Age
TV Hrs
1
43
1
2
30
6
3
22
4
4
20
3
5
5
6
Create an ANOVA table. Using α = .05use the results in the table
to give a conclusion about whether or not there is a statistically
significant linear relationship between the two variables. Your
score will be...
Adults around the world watch on average 4 hours of TV a day. A researcher thinks...
Adults around the world watch on average 4 hours of TV a day. A
researcher thinks that Americans watch less TV than the
international average. He finds 25 Americans who watch 3 hours of
television a day on average, with a standard deviation of 2 hours.
Using an Alpha = .05, test this hypothesis.
BE SURE TO ANSWER ALL PARTS OF THE QUESTION AND SHOW YOUR WORK
WHEN YOU CAN.
a) What is the appropriate test?
b) State the null...
a consultant for a large university studied the number of hours per week freshmen watch tv...
a consultant for a large university studied the number of hours
per week freshmen watch tv versus the number of hours seniors do.
the results of this study follow. is there enough evidence to show
the mean number of hours per week freshmen watch tv is different
from the mean number of hours seniors do at alpha=.1. freshmen
n=10, xbar=18.6, s=7.8740 seniors n=4, xbar=11.4, s=3.9749
a consultant for a large university studied the number of hours per week freshmen watch tv...
a consultant for a large university studied the number of hours
per week freshmen watch tv versus the number of hours seniors do.
the results of this study follow. is there enough evidence to show
the mean number of hours per week freshmen watch tv is different
from the mean number of hours seniors do at alpha=.1. freshmen
n=10, xbar=18.6, s=7.8740 seniors n=4, xbar=11.4, s=3.9749
A consultant for a large university studied the number of hours per week freshmen watch TV...
A consultant for a large university studied the number of hours
per week freshmen watch TV versus the number of hours seniors do.
The result of this study follow. Is there enough evidence to show
the mean number of hours per week freshman watch TV is different
from the mean number of hours seniors do at alpha= 0.01?
Freshmen
Seniors
n
8
4
xbar
18.2
11.9
s
7.8740
3.9749
For the Hypothesis stated above (in terms of Seniors-
Freshmen)
What...
Researchers sample 3000 households concerning tv shows they watch. Based on the sample 15% reported watching...
Researchers sample 3000 households concerning tv shows they watch.
Based on the sample 15% reported watching 60 minutes. What is the
95% confidence interval for the proportion of all Americans that
watch 60 minutes
How much Tv do you watch each week? A random sample of 41 adults were asked...
How much Tv do you watch each week? A random sample of 41 adults
were asked this question and thee mean found to be 3.9 hours with
standard deviation 1.6 hours.
a. Find the 99% confidence interval for the population mean
number of hours of TV watched each week.
b. Is it thought that most adults watch 3 hours of TV each week.
Do the data support this? Why of why not?
c. What is the margin of error in...
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