In: Advanced Math
Probabilities
Compute P(X1 + 2X2 -2X3 > 7) , where X1, X2, X3 are iid random variables with common distribution N(1,4). You must give the numerical answer.
Specify and show any formulas used for E, P, and Var
for example Var( X1 + 2X2 -2X3) = 4 + 22(4) + (-2)2(4) = 35. Please specify how all the individual numbers where obtained and the formula used.
Consider the following formula:
(i) For Independent and identically distributed (i.i.d.) random variables x1, x2 and constant a & b,
Var(aX1+bX2) = a2Var(X1) + b2Var(X2)
(ii) For random variables x1, x2 and constant a & b,
E(aX1+bX2) = aE(X1) + bE(X2)
(iii) For any real value a and continuous random variable X,
P(X>a) = 1-P(x<=a)
Solution:
X1, X2, X3 are i.i.d. random variables with N(1,4). So,
for each i = 1,2,3; E(xi) = 1 and Var(Xi) = 4.
Let Y = X1+2X2-2X3
Mean of Y is
E(Y) = E(X1+2X2-2X3) = E(X1) + 2E(X2) -2E(X3) (From (ii))
= 1+2(1)-2(1) = 1
Var(Y) = Var(X1+2X2-2X3) = Var(X1) + 22Var(X2) + (-2)2Var(X3) (from (i))
= 4 + 22(4) + (-2)24 = 36
So deviation of Y = (Var(Y))1/2 = (36)1/2 = 6
So, P(X1+2X2-2X3>7) = P(Y>7) = 1 - P(Y<=7) = 1 - P((Y - E(Y))/(deviation of Y) <= (7 - E(Y))/(deviation of Y) )
= 1 - P((Y - 1)/6 <= (7 - 1)/6 )
= 1 - P(Z <= 1) (Z = (Y - 1)/6 is a standard normal variable)
= 1 - Phi(1)
= 1 - 0.8413 (From standard normal table )
= 0.1587