In: Chemistry
Calculate the value of Eocell for the following reaction: 2Co3+(aq) + 3Ca(s) --> 2Co(s) + 3Ca2+(aq) Co3+(aq) + 3e– --> Co(s) Eo = 1.54 V Ca2+(aq) + 2e– --> Ca(s) Eo = –2.87 V.
A. –1.33 V
B. +1.33 V
C. –4.41 V
D. –11.6 V
E. +4.41 V
Since the reduction potential of Co3+ is more it is the cathodic reaction,so the
Standard potential of the cell , Eo = Eocathode - Eoanode
= EoCo3+/Co - EoCa2+/Ca
= +1.54 - (-2.87) V
= +1.33 V
Therefore the correct option is (B)