Calculate the Kc for the following reaction at 25 °C: Mg(s) + Pb2+(aq)?Mg2+(aq) + Pb(s) Kc...

Calculate the Kc for the following reaction at 25 °C: Mg(s) + Pb2+(aq)?Mg2+(aq) + Pb(s) Kc = × 10 Enter your answer in scientific notation.

Expert Solution

queen_honey_blossom answered 2 years ago

1)1. You are given the following cell at 25°C: Pb(s) | Pb2+(aq, 0.60M) || Sn2+(aq, 0.1...

1)1. You are given the following cell at 25°C: Pb(s) | Pb2+(aq, 0.60M) || Sn2+(aq, 0.1 M), Sn4+(aq, 0.15 M) |Pt(s) Write the half reactions for the cell and using Appendix D in your text book, calculate the E°cell and the Ecell oxidation half reaction = Pb(s) ------------> Pb+2(aq) + 2e- reduction half reaction = Sn+4(aq) + 2e- --------> Sn+2(aq) E0cell = E0Sn+4/sn+2 E0Pb+2/Pb E0cell = 0.15 - (-0.126) E0cell = 0.276 V ( i'm not sure if it correct...

Consider the reaction Mg(s)+Fe2+(aq)→Mg2+(aq)+Fe(s) at 89 ∘C , where [Fe2+]= 3.00 M and [Mg2+]= 0.110 M...

Consider the reaction Mg(s)+Fe2+(aq)→Mg2+(aq)+Fe(s) at 89 ∘C , where [Fe2+]= 3.00 M and [Mg2+]= 0.110 M . Part A: What is the value for the reaction quotient, Q, for the cell? Part B: What is the value for the temperature, T, in kelvins? Part C: What is the value for n? Part D: Calculate the standard cell potential for Mg(s)+Fe2+(aq)→Mg2+(aq)+Fe(s)

Consider the reaction Mg(s)+Fe2+(aq)→Mg2+(aq)+Fe(s) at 73 ∘C , where [Fe2+]= 3.70 M and [Mg2+]= 0.310 M...

Consider the reaction Mg(s)+Fe2+(aq)→Mg2+(aq)+Fe(s) at 73 ∘C , where [Fe2+]= 3.70 M and [Mg2+]= 0.310 M . What is the value for the reaction quotient, Q, for the cell? What is the value for the temperature, T, in kelvins? What is the value for n? Calculate the standard cell potential for Mg(s)+Fe2+(aq)→Mg2+(aq)+Fe(s)

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Consider the reaction Mg(s)+Fe2+(aq)→Mg2+(aq)+Fe(s) at 63 ∘C , where [Fe2+]= 2.90 M and [Mg2+]= 0.210 M . Part A What is the value for the reaction quotient, Q, for the cell? Express your answer numerically. Q = 7.24×10−2 SubmitHintsMy AnswersGive UpReview Part Correct Part B What is the value for the temperature, T, in kelvins? Express your answer to three significant figures and include the appropriate units. T = 336 K SubmitHintsMy AnswersGive UpReview Part Correct Part C What is...

1. A voltaic cell is constructed that is based on the following reaction: Sn2+(aq)+Pb(s)→Sn(s)+Pb2+(aq). a. If...

1. A voltaic cell is constructed that is based on the following reaction: Sn2+(aq)+Pb(s)→Sn(s)+Pb2+(aq). a. If the concentration of Sn2+ in the cathode compartment is 1.50 M and the cell generates an emf of 0.22 V , what is the concentration of Pb2+ in the anode compartment? b. If the anode compartment contains [SO2−4]= 1.50 M in equilibrium with PbSO4(s), what is the Kspof PbSO4? 2. A voltaic cell is constructed with two silver-silver chloride electrodes, each of which is...

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A voltaic cell is constructed that is based on the following reaction: Sn2+(aq)+Pb(s)→Sn(s)+Pb2+(aq). 1. If the concentration of Sn2+ in the cathode compartment is 1.50 M and the cell generates an emf of 0.25 V , what is the concentration of Pb2+ in the anode compartment? 2.If the anode compartment contains [SO2−4]= 1.00 M in equilibrium with PbSO4(s), what is the Ksp of PbSO4?

A voltaic cell is constructed that is based on the following reaction: Sn2+(aq)+Pb(s)→Sn(s)+Pb2+(aq). Part A If...

A voltaic cell is constructed that is based on the following reaction: Sn2+(aq)+Pb(s)→Sn(s)+Pb2+(aq). Part A If the concentration of Sn2+ in the cathode compartment is 1.50 M and the cell generates an emf of 0.18 V , what is the concentration of Pb2+ in the anode compartment? Part B If the anode compartment contains [SO2−4]= 1.40 M in equilibrium with PbSO4(s), what is the Ksp of PbSO4?

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21. What is the cell potential for the following cells at 25°C? a. Pb(s) | Pb2+ (aq) (1.0 M) || Cu2+ (aq) (1.0x10-4 M) | Cu(s) b. Pt(s) | Sn2+ (aq) (0.001 M), Sn4+(aq) (0.005 M) || Ag+(aq) (0.500 M) | Ag(s) c. In part a, what will the concentration of Pb2+ be at equilibrium? 22. The following cell has a measured potential of 1.42 V at 25°C: Al (s) | Al3+ (aq) (0.01 M) || Co2+ (aq) (? M)...

An electrochemical cell is based on the following two half-reactions: Ox: Pb(s)→Pb2+(aq,Pb(s)→Pb2+(aq, 0.15 MM )+2e−)+2e− Red:...

An electrochemical cell is based on the following two half-reactions: Ox: Pb(s)→Pb2+(aq,Pb(s)→Pb2+(aq, 0.15 MM )+2e−)+2e− Red: MnO−4(aq,MnO4−(aq, 1.80 MM )+4H+(aq,)+4H+(aq, 1.9 MM )+3e−→)+3e−→ MnO2(s)+2H2O(l) Compute the cell potential at 25 ∘C∘C.

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