Question

3. A graduated cylinder is filled with 50 mL of water . An aluminum cylinder is dropped , the water rises to 58 mL . As you also add a copper cylinder , the water rises to 64 mL . If the mass of the copper cylinder is 40 grams , find the density of the copper cylinder in g/mL.

a) 5 g/mL

b) 6.7 g/mL

c) 2.9 g/mL

d) 40 g/mL

3. A graduated cylinder is filled with 50 mL of water . An aluminum cylinder is dropped , the water rises to 58 mL . As you also add a copper cylinder , the water rises to 64 mL . If the mass of the copper cylinder is 40 grams , find the density of the copper cylinder in g/mL.

a) 5 g/mL

b) 6.7 g/mL

c) 2.9 g/mL

d) 40 g/mL

4. The electric face between two charged particles is F . as the distance between the two charges m the new force will be .

a) 2F

b) 4F

c) F/2

d) F/4

Answer 1

3.) The idea here is that the increase in the volume of water in the cylinder is due to the volume of the cylinder which is dropped.

This means that you can figure out the volume of the dropped cylinder, by looking at the volume occupied by the water + dropped cylinder and at the volume occupied by the water alone in the cylinder.

Ans : Option (b) 6.7 g/mL

​​​​​​​4.) I think question is not typed correctly, so i will give an idea to do this question according to the options,

The force between the two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.

• If distance between charges is halved i.e. r/2 (charges remaining kept constant),

The force between the two charges is quadrupled., Means 4F.

• if the distance between the two charges is doubled, i.e. 2r ​, ​​​The attraction or repulsion becomes weaker, decreasing to one-fourth of the original value. i.e. F/4.