Alpha particles of a certain initial kinetic energy are projected at nuclei with atomic number Z...

Alpha particles of a certain initial kinetic energy are projected at nuclei with atomic number Z = 60. The closest distance of approach of the alpha particles to the nucleus is 100 fm (fm = femtometer = 10^-15 m). If alpha particles of the same initial kinetic energy are projected at nuclei with atomic number 88, what is the distance of closest approach? Give your answer in fm. (Enter the number only -- do not include the units in your answer.)

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Expert Solution

Comment the distance of closest approach for the nucleus with z=88 was found to 146.667 FM.

genius_generous answered 2 years ago

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