In: Statistics and Probability
The contingency table below shows the results of a random sample of 200 state representatives that was conducted to see whether their opinions on a bill are related to their party affiliations.
Test the claim of independence. Use α = .05.
Answer:
Here iam assuming the missing data to solve this problem
here we will use chi-square test of independence
let H0 : opinion on a bill are related to their party affiliation
Ha : opinion on a bill are not related to their party affiliation
using excel >phstat> chi square test we have
Observed Frequencies | ||||||||
opinion | Calculations | |||||||
party | Approve | Dispprove | No opinion | Total | fo-fe | |||
Republician | 42 | 20 | 14 | 76 | 3.24 | -2.8 | -0.44 | |
Democrat | 50 | 24 | 18 | 92 | 3.08 | -3.6 | 0.52 | |
Independent | 10 | 16 | 6 | 32 | -6.32 | 6.4 | -0.08 | |
Total | 102 | 60 | 38 | 200 | ||||
Expected Frequencies | ||||||||
opinion | ||||||||
party | Approve | Dispprove | No opinion | Total | (fo-fe)^2/fe | |||
Republician | 38.76 | 22.8 | 14.44 | 76 | 0.270836 | 0.34386 | 0.013407 | |
Democrat | 46.92 | 27.6 | 17.48 | 92 | 0.202182 | 0.469565 | 0.015469 | |
Independent | 16.32 | 9.6 | 6.08 | 32 | 2.447451 | 4.266667 | 0.001053 | |
Total | 102 | 60 | 38 | 200 | ||||
Data | ||||||||
Level of Significance | 0.05 | |||||||
Number of Rows | 3 | |||||||
Number of Columns | 3 | |||||||
Degrees of Freedom | 4 | |||||||
Results | ||||||||
Critical Value | 9.487729 | |||||||
Chi-Square Test Statistic | 8.03049 | |||||||
p-Value | 0.090468 | |||||||
Do not reject the null hypothesis |
Since calculated value 8.03049 is less than 9.487729 so we do not reject Ho and conclude that opinion on a bill are related to their party affiliation
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