Question

In: Statistics and Probability

A 1970s case-control study on cerebrovascular disease (thrombotic stroke) and oral contraceptive use in young women...

A 1970s case-control study on cerebrovascular disease (thrombotic stroke) and oral contraceptive use in young women matched cases to controls according to neighborhood, age, sex, and race. The table below displays data from this study for thrombotic stroke. Perform an appropriate test at alpha level 5%.

Case exposed

Case Not exposed

Control exposed

2

5

Control Not exposed

44

55

  1. Which test is appropriate to test the association between cerebrovascular disease (thrombotic stroke) and oral contraceptive use? Why?

  2. State null and alternative hypotheses.

  3. Compute a test statistics.

  4. Compute a p-value using an appropriate table.

  5. Can you reject the null hypothesis at alpha level 5%?

  6. State your conclusion.

Solutions

Expert Solution

We will use a Chi-Square Independence test. This is because we have categorical and count data and want to find whether there is ascoocation between the two vairables.

Chi-Square Independence test
(1) Null and Alternative Hypotheses
The following null and alternative hypotheses need to be tested:
H0​: The two variables - cerebrovascular disease and oral contraceptive use are independent
Ha​: The two variables - cerebrovascular disease and oral contraceptive use are dependent

This corresponds to a Chi-Square test of independence.

(2) Degrees of Freedom
The number of degrees of freedom is df = (2 - 1) * (2 - 1) = 1

(3) Critical value and Rejection Region
Based on the information provided, the significance level is α=0.05, the number of degrees of freedom is df = (2 - 1) * (2 - 1) = 1, so the critical value is 3.8415.
Then the rejection region for this test becomes R={χ2:χ2>3.8415}.

(4)Test Statistics
The Chi-Squared statistic is computed as follows:

(5)P-value
The corresponding p-value for the test is p=Pr(χ2​>0.6706)=0.4129

(6)The decision about the null hypothesis
Since it is observed that χ2=0.6706<χ2_c​rit=3.8415, it is then concluded that the null hypothesis is NOT rejected.

(7)Conclusion
It is concluded that the null hypothesis Ho is NOT rejected. Therefore, there is NOT enough evidence to claim that the two variables - cerebrovascular disease and oral contraceptive use are dependent, at the 0.05 significance level.

Conditions:
a. The sampling method is simple random sampling.
b. The data in the cells should be counts/frequencies
c. The levels (or categories) of the variables are mutually exclusive.

Let me know in the comments if anything is not clear. I will reply ASAP! Please do upvote if satisfied!


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