In: Chemistry
At 700 K, CCl4 decomposes to carbon and chlorine. The Kp value for the decomposition is 0.76. Find the starting pressure of CCl4 at this temperature that produces a total pressure of 1.7 atm at equilibrium.
CCl4(g) C(s) + 2Cl2(g)
Initial a 0
Equilibrium a-x 2x
Total pressure at equilibrium = a – x + 2x = a + x
Given, Total pressure at equilibrium = 1.7 atm
Therefore,
a = 1.7 – x
Kp = PCl22/PCCl4
0.76 = (2x)2/(a-x) = 4x2/ (1.7 – 2x)
4x2 + 1.52 x – 1.292 = 0
On solving,
x = 0.409
a + x = 1.7 atm
a = 1.7 atm - 0.409 atm = 1.291 atm
Starting pressure of CCl4 = 1.291 atm