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At 700 K acetaldehyde decomposes in the gas phase to methane and carbon monoxide. The reaction...

At 700 K acetaldehyde decomposes in the gas phase to methane and carbon monoxide. The reaction isCH3CHO(g)?CH4(g)+CO(g)
A sample of CH3CHO is heated to 700 K and the pressure is measured as 0.20 atm before any reaction takes place. The kinetics of the reaction are then followed by measurements of total pressure and these data are obtained:

t(s) 0 1000 3000 7000
PTotal (atm) 0.20 0.22 0.24 0.28

Rate law --> Rate=??PCH3CHO?t=4.510?4atm?1?s?1PCH3CHO2

Find total pressure after 1.17104s

Solutions

Expert Solution

The reaction is:

        CH3COH(g)                ?     CH4(g)          +          CO(g)

At t=0:        0.2 atm            0               0

A t=t:         0.2 -x                x               x

Ptotal= P(CH3COH) + P(CH4) +P(CO)= 0.2 - x + x + x = 0.2 + x

x = Ptotal -0.2 (atm)

At t=0 s: x = 0 atm ?P(CH3COH) = 0.2 atm

At t = 1000 s: x = 0.02 atm ?P(CH3COH) = 0.18 atm

At t = 3000 s: x = 0.04 atm ?P(CH3COH) = 0.16 atm

At t = 3000 s: x = 0.08 atm ?P(CH3COH) = 0.12 atm

The rate law of the reaction is: rate = r = -d{P(CH3COH)/dt = k


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