Question

In: Statistics and Probability

Wendy’s is offering a new Wolfburger as a promotional tie-in for the new sequel in the...

Wendy’s is offering a new Wolfburger as a promotional tie-in for the new sequel in the Twilight motion picture series, and wonders how much they should charge. It test-markets five different prices in the cities listed below, with the listed resultant sales (in thousands of dollars):

City

Sales($000s)

Price($)

Price2

Sales2

Price*Sales

Rochester

75

0.99

0.98

5625.00

74.3

Ottumwa

70

1.29

1.66

4900.00

90.3

Seattle

45

1.49

2.22

2025.00

67.1

Raleigh

33

1.89

3.57

1089.00

62.4

Denair

42

2.19

4.80

1764.00

92.0

sum

265

7.85

13.23

15403.00

386.0

mean

53

1.57

2.65

3080.60

77.2

st.dev.

18.4

0.5

1.53

2037.06

13.4

a.) Compute (numerically) and interpret (in words) the correlation between sales and price
b. ) Estimate the regression function between sales and price

Solutions

Expert Solution

a.

X Values
∑ = 601.4
Mean = 75.175
∑(X - Mx)2 = SSx = 43565.315

Y Values
∑ = 17.77
Mean = 2.221
∑(Y - My)2 = SSy = 38.098

X and Y Combined
N = 8
∑(X - Mx)(Y - My) = 1222.75

R Calculation
r = ∑((X - My)(Y - Mx)) / √((SSx)(SSy))

r = 1222.75 / √((43565.315)(38.098)) = 0.9491

b.

Sum of X = 601.4
Sum of Y = 17.77
Mean X = 75.175
Mean Y = 2.2213
Sum of squares (SSX) = 43565.315
Sum of products (SP) = 1222.7503

Regression Equation = ŷ = bX + a

b = SP/SSX = 1222.75/43565.32 = 0.0281

a = MY - bMX = 2.22 - (0.03*75.18) = 0.1113

ŷ = 0.0281X + 0.1113


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