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11) In the reaction of nitrogen gas with hydrogen gas to form ammonia gas, NH3, bow...

11) In the reaction of nitrogen gas with hydrogen gas to form ammonia gas, NH3, bow many grams of hydrogen are needed to react with two moles of nitrogen?

Solutions

Expert Solution

The balanced equation is   : N2 + 3H2 2NH3

According to the balanced equation,

1 mole of N2 reacts with 3 moles of H2

2 moles of N2 reacts with M moles of H2

M = ( 2x3)/1

    = 6 moles

Molar mass of H2 = 2xAt.massof H = 2x1 = 2 g/mol

We know that number of moles , n = mass/ molar mass

So mass of H2 needed , m = number of moles x molar mass

                                        = 6 mol x 2 g/mol

                                        = 12 g

Therefore the mass of hydrogen needed is 12g

queen_honey_blossom answered 1 year ago
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