Question

In: Biology

You cross a mutant with phenotype 'a b c^+' to a mutant with the phenotype 'a^+b^+c'...

You cross a mutant with phenotype 'a b c^+' to a mutant with the phenotype 'a^+b^+c' and test cross the F1. Given this genetic map, predict the phenotypes observed in the offspring, and the number of each expected in a population of 2500 (show your work).

c < 19 m.u. > a <8 m.u. > b

Solutions

Expert Solution

The steps involved in this problem:

1. Calculation of DCO from COC
2. Calculation of SCO and
3. Calculation of PCO.

1. Calculation of DCO freequency :
As the interference not mentioned here, providing the solution by taking the interference as 0. so,

COC = 1.
COC = Prop of ODCO/ Prop of EDCO.
=> 1 = Prof of ODCO/ (19/100 X 8/100) => DCO = 1 X 0.19 X 0.08 = 0.0152


The Freequency of DCO = 0.0152 *1000 = 38.


2. Calculation of SCO:.
The Distiance between two genes= Prop of SCO+ Prop of DCO.
So, Prop of SCO = Distiance between two genes - Prop of DCO.
The freequency = Prop of SCO * Total no of progeny


Between first pair of genes =
The Distance = 19, The proportion = 19/100 = 0.19
Prop of SCO = 0.19- 0.0152 = 0.1748
The freequency = 0.1748 * 2500 = 437.


Between second pair of genes =
The Distance = 8, The proportion = 8/100 = 0.08
Prop of SCO = 0.08- 0.0152 = 0.0648
The freequency = 0.0648 * 2500 = 162.

3. Calculation of PCO:

Parental combinations = Total freequency - SCO - DCO
=> 2500- 437 - 162- 38 = 1863


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