In: Statistics and Probability
Question 3: Hypothesis Testing about the population mean
(μ)
A researcher claims that the average weekly spending for lunch by
commuting students in US colleges is usually higher in winter
semester than the of average of $30 in the prior fall semester. To
verify this claim a sample of 100 commuting students were randomly
selected in spring semester and their average weekly spending was
reported as $32.5. From historical experience the population
standard deviation of weekly spending by commuting students
nationally is known to be $12.6. Use this information to answer
these questions.
Note: Standard error
of is
OR
1. In the context of this problem, μ denotes
……………………..
2. This is a case 1, 2 or 3 (circle one)
hypothesis testing problem because ……………
………………… and ………………………….
3. Based on your answer in part
2, can only be transformed into (choose
one)
Z = (
- ) ( )
OR
t = ( - ) ( S)
4a. From the three exhibits below, which pair
of hypotheses would you use to verify the researcher’s
claim.
(2
points.)
Exhibit 1
H0: µ ≤ 30
Ha: µ < 30
Exhibit 2
H0: µ ≤
30
Ha: µ > 30
Exhibit 3
H0:
µ 30
Ha: µ < 30
b. From your choice in part ‘a’, which hypothesis
(H0 or Ha) reflects/represents the research
question?
c. From your answer in part 3 above, the standard
error of the sample mean is ..................
5a. At α = .05, the p-value (PV) is
............................................
b. At α = .05, state the decision rules for
rejecting or not rejecting H0.
c. At α = .05, what is your conclusion?
6. Repeat the hypothesis test using the critical value (CV) approach.
a. At α = .05, state the decision rules for rejecting or not rejecting H0.
b. At α = .05, what is your conclusion?
1. The population mean (μ) be the average weekly spending for lunch by commuting students in US colleges.
2. The hypothesis is test is one-tailed Z-test because the population standard deviation known.
3.
4.
(a) Hypothesis: Vs
(b) The alternative hypothesis Ha represents the research question.
(c) The standard erorr is ,
5.
(a) The test statistic is ,
The p-value is ,
p-value=
; From standard normal distribution table
(b) Decision rule : Reject Ho , if p-value <
Here , p-value=0.0239<=0.05
Therefore , reject Ho.
(c) Conclusion : At =0.05 , there is sufficinet evidence to to support the claims that the average weekly spending for lunch by commuting students in US colleges is usually higher in winter semester than the of average of $30 in the prior fall semester.
6.
The critical value is ,
; From Z-table
(a) Decision rule : Reject Ho , if Z-stat>1.64
Here , Z-stat=1.98>1.64
Therefore , reject Ho.
(b) Conclusion : At =0.05 , there is sufficinet evidence to to support the claims that the average weekly spending for lunch by commuting students in US colleges is usually higher in winter semester than the of average of $30 in the prior fall semester.