Question

Closest and Farthest points. Distance between two points (x1, y1) and (x2, y2) can be
calculated as d = sqt( (x1 − x2) ^2 + (y1 − y2)^ 2)
. You are given the coordinates of a source
point and three destination points. Write a Python program stored in a file q8.py that
takes these information as input and determines the closest and farthest destination
points from the source point.

ex:

Enter source coordinates : 0 0
Enter point A coordinates : 1 4
Enter point B coordinates : -4 5
Enter point C coordinates : -2.4 -0.9

From source point (0.0 , 0.0) ,
Point C ( -2.4 , -0.9) is closest , with distance of 2.56 units .
Point B ( -4.0 , 5.0) is farthest , with distance of 6.4 units

Answer 1

def readPoint(prompt):
        points = input(prompt)
        points = points.split()
        return float(points[0]), float(points[1])

def distance(p1, p2):
        return ((p1[0] - p2[0]) ** 2 + (p1[1] - p2[1]) ** 2) ** 0.5

points = []

points.append(readPoint('Enter source coordinates : '))
points.append(readPoint('Enter point A coordinates : '))
points.append(readPoint('Enter point B coordinates : '))
points.append(readPoint('Enter point C coordinates : '))

# assume first point to be result
maxDis = distance(points[0], points[1])
maxDisPoint = points[1]
minDis = distance(points[0], points[1])
minDisPoint = points[1]

# check if better points are present
for i in range(2, len(points)):
        d = distance(points[0], points[i])
        if d > maxDis:
                maxDis = d
                maxDisPoint = points[i]
        if d < minDis:
                minDis = d
                minDisPoint = points[i]

print('From source point', points[0])
print('Point', minDisPoint, ' is closest, with distance of', minDis, 'units')
print('Point', maxDisPoint, ' is farthest, with distance of', maxDis, 'units')