The questions below refer to a solution of butanoic acid, CH3(CH2)2-COOH, in water. The solution was...

The questions below refer to a solution of butanoic acid, CH3(CH2)2-COOH, in water. The solution was formed by adding 1.15 g of butanoic acid to enough water to make 100 mL of solution at 298K.

1. What is the initial butanoic acid concentration in the solution in moles per liter?

2. What is the pH of this solution?

3. How many mL of a 1.095 M NaOH solution would have to be added to the butanoic acid solution in order to completely neutralize the acid?

4. What will be the pH of the solution at the equivalence point, i.e. when all of the acid has reacted with the NaOH?

Expert Solution

queen_honey_blossom answered 3 years ago

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