75mL of a 0.111 mol L-1 solution of butanoic acid(H3CCH2CH2C(=O)OH), and 38 mL of a solution...

75mL of a 0.111 mol L^-1 solution of butanoic acid(H₃CCH₂CH₂C(=O)OH), and 38 mL of a solution of KOH of molarity 0.101 mol L^-1 are mixed in a 250 mL beaker. What would be the resulting solution's pH?

Expert Solution

queen_honey_blossom answered 1 year ago

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