Question

1) Jazz is a 172 lb athlete who exercised at 7.6 METs. At this workload, what is his energy expenditure in kcals/min.? Round to the nearest whole number.

A. 10 kcals/min B. 12 kcals/min C. 15 kcals/min D. 7 kcals/min

2) Which type of calorimetry is the most practical to use in quantifying energy expenditure? A. Direct Calorimetry B. Indirect Calorimetry C. Open-Circuit D. Closed-Circuit

3) When is it appropriate to use the term non-protein RQ? A. During a non-steady state of exercise B. During a period of exercise when hyperventilation occurs C. During a steady state of exercise D. None of the above

4) Ashley is a 130 lb athlete who biked on a cycle ergometer at a steady state of exercise for 48 minutes. Her average VO2 was 2.72 LO2/min. and her average VCO2 was 2.24 LCO2/min. What was her total energy expenditure (in kcals) during the entire bout of exercise? Round to the nearest whole number.

A. 712 kcals B. 687 kcals C. 603 kcal D. 630 kcals

5) Carleton is a 155 lb athlete who exercised at a relative VO2 of 34 mlsO2/kg min. At this workload what is his energy expenditure in METs? Round to the first decimal place. A. 10.3 METs B. 8.2 METs C. 9.7 METs D. 8.6 METs

Answer 1

1.Energy expenditure(kilocalories/minute)=0.0175XMETXweight in Kilograms, Here MET=7.6,Weight in kg =172/2.2=78

Energy Expenditure=0.0175X7.6x78=10.3k.cal/min ------------ OPTION-A

2. Indirect Calorimetry calculates the amount of energy expenditure from the amount of oxygen consumed and Carbondioxide produced.It is easy to calculate the amount of energy expenditure based on amount of oyxgen and carbondioxide.

Indirect Calorimetry is the most practical use in quantifying energy expenditure --------- OPTION-B

3.During a steady state of exercise,It is appropriate to use the term non-protein RQ ------- OPTION-C

4. Energy expenditure(K.cal/Day)=1.44X[3.941XVO₂(mL/min)+1.11XVCO₂(mL/min)] V0₂=2.72L/min=2720mL/min

VCO₂=2.42L/min=2420mL/min

Energy expenditure= 1.44X[3.941x2720+1.11X2420]=1.44X[10,719+2686]=1.44X13405=19,303 Kcal/day

19,303 Kcal/day 1440min 1 day=1440 min

?    48 min 19303X48/1440=633 Kcal 630Kcal ------------- OPTION-D

5.Energy Expenditure(K.cal/Min)=0.0175XMETX weight in Kilograms here MET=VO₂/3.5=9.7,Weight in kG=155/2.2=70 Kg

Energy Expenditure=0.0175X9.7X70=12.25Kcal/min 12.25X60=735Kcal/Hr

1 MET=K.Cal/KgXHour here K.cal=735,Weight In kg=70,Time In Hours=1 so

MET = 735/70X1=10.5 10.3 METs -------------OPTION - A