Question

1 Vince, a 180 lb athlete, performs the vertical jump test. His standing reach is 82 inches, and his highest jump is 107 inches. What is his power output in Watts (1 Watt = 0.1020 kgm/sec.)? Round your answer to the first decimal place. A. 1525.7 Watts B. 2097.4 Watts C. 1863.5 Watts D. 1412.6 Watts

Question 2 Turtle (220 lb individual) performs the Margaria-Kalamen leg power test (stair test). His time between the 3rd and 9th steps is 0.75 seconds (each step is 6 inches in height). What is his power output in kgm/sec? Round your answer to the nearest whole number. A. 157 kgm/sec. B. 135 kgm/sec. C. 122 kgm/sec. D. 110 kgm/sec.

Question 3 Jennifer is a 140 lb athlete who performed the Margaria-Kalamen leg power test (stair test). Her time between the 3rd and 9th steps was 0.58 seconds (each step is 7 inches in height). What was her power output in Watts (1 Watt = 0.1020 kgm/sec.)? Round your answer to the nearest whole number. A. 1298 Watts B. 1148 Watts C. 1162 Watts D. 1079 Watts

Question 4 Among the three energy systems which one produces ATP at the fastest rate? A. Oxidative Energy System B. Aerobic Energy System C. Anaerobic Glycolysis D. ATP-PCR 5) Amanda is a 115 lb athlete who performed the 30-second Wingate test. Her peak power output was 559 Watts, and her lowest power output was 332 Watts. What was her anaerobic fatigue (percent decline in power output)? Round your answer to the first decimal place. A. 40.6 % B. 55.4 % C. 49.8 % D. 37.2 %

Answer 1

answer) the formula for power is given by

P=work done /time

P=W/t

and work done=Force *distance

W=F*d

here we have

F=mg

m=180lb=81.65 kg

g=9.8m/s²

so F=81.65*9.8=800.17N

the total jump height is 107-82=25 inches

and 25 inches=0.635 m

so now we can calculate the work done

W=800.17*0.635=508.11 J

now we know from newtons law

s=ut+1/2gt²

the body starts from rest, so u=0

0.635m=1/2*9.8*t²

t=0.635/4.9=0.36s

so now P=508.11J/0.36s=1412.6 watts

so correct option is 1412.6 watts

2) we know the formula for power

P=W/t

and work done W=F*d

F=m*g=99.79kg*9.8=979.906N

distance of one step=6 inches=0.1524m

so W=979.906*0.1524=149.04J

time taken between 3 to 9 steps is =0.75s

but we need time for each step, there are 6 steps in between 3-9 so

t=0.75/6=0.125s

now we have everything we need

P=149.04J/0.125s=1192.31Watts

we need the answer in kgm/s

so 1192.31*0.1020=122 kgm/s

so the correct answer is 122 kgm/s

3) again using the same formula we have

power=W/t

work done=F*d

F=mg

m=140lb=63.5 kg

F=63.5*9.8=622.3N

here d=7 inches=0.1778m

so W=622.3*0.1778m=110.645J

time between 3rd and 9th step=0.58s,

so for each step time=0.58/6=0.0967s

now we have everything we need

P=W/t=110.645J/0.0967s=1144.209 watts

this answer is close to 1148 . so correct answer is 1148 watt.