In: Statistics and Probability
Exercise 3
In a study, randomly selected records of 140 crimes reveal that they were committed on the following days of the week.
| 
 Day  | 
 Monday  | 
 Tuesday  | 
 Wednesday  | 
 Thursday  | 
 Friday  | 
 Saturday  | 
 Sunday  | 
| 
 Number of crime  | 
 17  | 
 21  | 
 22  | 
 18  | 
 23  | 
 24  | 
 15  | 
Please answer the following questions underneath each question.
1. Which test is appropriate to to examine whether crimes are equally likely to be
committed on any day
Answer:
2. Conduct the steps of this test
(please enumerate and write all the steps of your answer below)
Step 1:
3. State your conclusion in the context of this study
1. Test to be conducted: Chi square test of goodness of fit
Test that is used to find out if the observed value of a given phenomena is significantly different from the expected value
2.
Step 1:
Ho: The proportion of crime commited on all days of the week are equal; i.e. = 1/7
Ha: : Some of the population proportions differ from the values stated in the null hypothesis
Step 2: Chi square test stat
| Day | Observed values (fo)  | 
Expected Proportions | Expected values (fe)  | 
(fo-fe)2/ fe | 
| Mon | 17 | 0.143 | 20.00 | 0.450 | 
| Tue | 21 | 0.143 | 20.00 | 0.050 | 
| Wed | 22 | 0.143 | 20.00 | 0.200 | 
| Thur | 18 | 0.143 | 20.00 | 0.200 | 
| Fri | 23 | 0.143 | 20.00 | 0.450 | 
| Sat | 24 | 0.143 | 20.00 | 0.800 | 
| Sun | 15 | 0.143 | 20.00 | 1.250 | 
| Total | 140 | 1.000 | 140.00 | 3.400 | 

= 3.40
p value = 0.7572
Step 3:
As the level of significance is not given, taking 
 = 0.05, df = 7
Chi square critical = CHISQ.INV.RT(probability,df) = CHISQ.INV.RT(0.05, 6) = 5.348
Step 4: Decision
As 
 ( 3.40) is less than 
 critical, we fail to reject the Null hypothesis.
Hecne we dont have sufficient evidence to believe that no of crimes committed on differenet days during a week are different.