Consider the curve given by the equation y^2 - 2x^2y = 3 a) Find dy/dx. b)...

Consider the curve given by the equation y^2 - 2x^2y = 3

a) Find dy/dx.

b) Write an equation for the line tangent to the curve at the point (1, -1).

c) Find the coordinates of all points on the curve at which the line tangent to the curve at that point is horizontal. d) Evaluate d 2y /dx2 at the point (1, -1).

Expert Solution

milcah answered 1 year ago

find the differential equation of dy/dx = y+y^3

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