d^2y/dx^2 − dy/dx − 3/4 y = 0,
y(0) = 1, dy/dx(0) = 0,
Convert the initial value problem into a set of two coupled
first-order initial value problems
and find the exact solution to the differential equatiion
For the differential equation dy/dx=sqrt(y^2−36) does the
existence/uniqueness theorem guarantee that there is a solution to
this equation through the point
1. (1,6)
2. (4,42)
3. (−2,38)
4. (7,−6)
1.) (1 point) Find the particular antiderivative that satisfies
the following conditions:
dy/dx=7−4x; y(0)=2
y=
2.) (1 point) Find the particular antiderivative that satisfies
the following conditions:
p′(x)=−50/x^2; p(3)=7
p(x)=
3.) (1 point) Find the particular antiderivative that satisfies
the following conditions:
dx/dt= (5sqrt(t^3)-6t)/sqrt(t^3); x(9)=7
x=
4.) (1 point) Given
f′′(x)=3x−2
and f′(−2)=2 and f(−2)=4.
Find f′(x)=
and find f(3)=
5.) (1 point) Consider the function f(x)=10x10+10x7−5x4−2.
An antiderivative of f(x) is F(x)=Ax^n+Bx^m+Cx^p+Dx^q where
A is and n is
and B is:...