Question

A research psychologist wishes to investigate the difference in maze test scores for a strain of laboratory mice trained under different laboratory conditions. The experiment is conducted using eighteen randomly selected mice of this strain, with six receiving no treatment at all (control group), six trained under condition 1, and six trained under condition 2. Then each of the mice is given a test score between 0 and 100, depending on its performance in a test maze. The experiment produced the following results.

Control	Condition 1	Condition 2
58	73	53
32	70	74
59	68	72
64	71	62
55	60	58
49	62	61

Is there sufficient evidence to indicate a difference among mean maze test scores for mice trained under the three different laboratory conditions. Use a=.05. Perform multiple comparisons if necessary. Use a= .05. Can you please try and use minitab to show work. Thank you!

Answer:

H₀:

H_a:

a=.05

Value of the test statistic:

    P value:

State your conclusion:

Perform Multiple Comparisons using Tukey’s procedure if necessary.

Answer 1

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Summary and Conclusion:

The treatment means of maze test scores 2-1 is significantly different based on the t-value is 2.92 and the corresponding p-value is 0.027, which is less than the level of significance. Hence, We can justify that it is not necessary to conduct the multiple comparisons test for the given data.