The null and alternative hypotheses are: H0:μd≤0H0:μd≤0 H1:μd>0H1:μd>0 The following sample information shows the number of...

The null and alternative hypotheses are:

H0:μd≤0H0:μd≤0

H1:μd>0H1:μd>0

The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month.

	Day
	1	2	3	4
Day shift	10	12	15	18
Afternoon shift	8	9	13	16

At the 0.01 significance level, can we conclude there are more defects produced on the Afternoon shift?

a. State the decision rule. (Round the final answer to 3 decimal places.)

H₀ is (Click to select) rejected not rejected if t > .

b. Compute the value of the test statistic. (Round the final answer to 3 decimal places.)

Test statistic

c. What is your decision regarding the null hypothesis?

H₀ should (Click to select) not be rejected be rejected .

d. Determine the p-value. (Round the final answer to 4 decimal places.)

The p-value is .

Solutions

Expert Solution

H0:μd≤0

H1:μd>0

H₀ is rejected if t > 4.541

TS = 9

Null hypothesis is rejected

p-value = 0.0014

orchestra answered 1 year ago

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