In: Statistics and Probability
The null and alternate hypotheses are:
H0 : μd ≤ 0
H1 : μd > 0
The following sample information shows the number of defective units produced on the day shift and the afternoon shift for a sample of four days last month.
Day | ||||
1 | 2 | 3 | 4 | |
Day shift | 11 | 11 | 16 | 19 |
Afternoon shift | 10 | 9 | 14 | 16 |
At the 0.010 significance level, can we conclude there are more defects produced on the day shift? Hint: For the calculations, assume the day shift as the first sample.
State the decision rule. (Round your answer to 2 decimal places.)
Compute the value of the test statistic. (Round your answer to 3 decimal places.)
What is the p-value?
Between 0.005 and 0.01
Between 0.001 and 0.005
Between 0.01 and 0.025
What is your decision regarding H0?
Reject H0
Do not reject H0
(a)
(b)
Test statistic = 4.899
(c)
Ans : Between 0.005 and 0.01
(d) Reject H0 (by decision rule)