Question
In: Chemistry
Treatment of gold metal with BrF3 and KF produces Br2 and KAuF4, a salt of gold....
Treatment of gold metal with BrF3 and KF produces Br2 and KAuF4, a salt of gold. This is the balanced equation ; 2Au+2BrF3+2Kf=Br2+2KAuF4
(a) Assign oxidation numbers to each Au and Br atom involved in this reaction. SHOW WORK/EXPLAIN REASONING.
(b) Write the complete chemical formula of the oxidizing agent.
(c) Calculate the min mass of gold required to produce 73.5g of the KAuF4 product. Thank you!!
Solutions
queen_honey_blossom answered 2 years agoRelated Solutions
--Given Values-- Atomic Radius (nm) = 0.116 FCC Metal = Gold BCC Metal: = Sodium Temperature...
--Given Values--
Atomic Radius (nm) = 0.116
FCC Metal = Gold
BCC Metal: = Sodium
Temperature ( C ) = 1017
Metal A = Tin
Equilibrium Number of Vacancies (m-3) = 6.02E+23
Temperature for Metal A = 369
Metal B = Gallium
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