Question

I just need to find the specific heat of copper, steel and aluminum.

Experiment 12 Specific Heat Capacity [Calorimetry)

See the Introduction section onpage L2-2.
A metal sample of 'mass ms is heated in boiling water to a high temperature of Tl, - 101.3 oC. It is then quickly placed in a calorimeter cup of mass mc = 5T .9 grams containing liquid water of mass m*, both at an initial cool temperature T.. The specific heat capacity of liquid water is c* = 1.00 cal/g oC, and the specific heat capacity of the calorimeter cup is cc = 0.2L5 cal/g 'C. The heated metal sample and the cool cup and water eventually all come into equilibrium at temperature T.o.

Use energy balance: heat loss by metal sample = heat gain by calorimeter and water

See equation [1J, then solve for cr.

Use the following data to determine the specific heat capacity for copper, steel, and aluminum:

copper 56.0 steel 4B.B aluminum L7.6

73.8 25.6 56.0 26.0 58.7 24.6

m. (grams) m* fgrams) T. ("C)

T.q ("C) 30.0 31.8 28.4

Compare your results with Table I-4.

The calorie was historically defined as the amount of heat needed to change the temperature of 1.00 gram of liquid water by 1.00 'C fat sea level pressure), hence c* = 1.00 cal/ g "C by definition. L cal = 4.L86 | ISI equivalent)

Answer 1