In: Accounting
Show the work please
QX = b0 + b1 PX + b2 PR + b3 M
Assume R is a substitute and X is a normal good. The estimation results are reported below:
Dependent Variable: QX |
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Method: Least Squares |
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Date: 07/23/06 Time: 11:10 |
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Sample: 1 20 |
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Included observations: 20 |
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Variable |
Coefficient |
Std. Error |
t-Statistic |
P-Value |
C |
19.777074 |
1.784179 |
11.0846 |
0.0000 |
PX |
-13.79169 |
2.303381 |
-5.987587 |
0.0000 |
PR |
5.069939 |
0.844016 |
6.006920 |
0.0000 |
M |
0.257197 |
0.080063 |
3.212410 |
0.0054 |
R-squared |
0.872386 |
F-statistic |
36.45966 |
|
Adjusted R-squared |
0.848459 |
P-Value for F-statistic |
0.0000 |
a. Conduct t tests to see if the coefficients are statistically significant at the 5% level of significance. Disregard the intercept. Use the p-values. A simple yes or no is not enough. Explain
b. Conduct an F- test to see if the equation, as a whole, is statistically significant at the 5%. Use the p-value. A simple yes or no is not enough. Explain.
a.The t statistics square measure
already provided within the output. The t-test tests the alternate
hypothesis that the constant of the variable is zero (or the
variable is statistically significant).
For Px, p-value for the t-test = zero. At significance level of
fifty, 0 < 0.05. so p-value < significance level. thus PX is
statistically vital. this can be expected because the value of a
standard sensible can have an effect on the demand of the great. If
value will increase, individuals wouldn't be ready to purchase the
maximum amount of the great s they were shopping for before. it's
negatively associated with amount demanded of the traditional
sensible.
For PR, p-value for the t-test = zero. At significance level of
fifty, 0 < 0.05. so p-value < significance level. thus PR is
statistically vital. this can be expected because the value of a
complement will increase (decreases), the individuals would be
shopping for less (more) of the complement and additional (less) of
the traditional sensible. it's completely associated with the
quanitity demanded of the traditional sensible.
For M, p-value for the t-test = zero. At significance level of
fifty, 0.0054 < 0.05. so p-value < significance level. thus M
is statistically vital.
b.The F datum is goven up to thirty six.45966.
The F check tests that the equation as an entire is statistically
vital. p-value = zero. SInce p-value of zero < significance
level of zero.05, we tend to conclude that the model is
important.
c. R sq. is zero.872386. this can be on the point of one. It means
the model could be a excellent work. 87.24% of variation within the
quantitiy demanded is explained by the freelance variables.
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