In: Statistics and Probability
Construct the indicated confidence interval for the population mean u using a t-distribution.
c=0.98, x =112, s=10, n=15
The confidence interval is (_, _) (Round to the nearest tenth as needed.)
Solution :
Given that,
Point estimate = sample mean =
= 112
sample standard deviation = s = 10
sample size = n = 15
Degrees of freedom = df = n - 1 = 15 - 1 = 14
At 98% confidence level the t is ,
= 1 - 98% = 1 - 0.98 = 0.02
/ 2 = 0.02 / 2 = 0.01
t
/2,df = t0.01,14 = 2.624
Margin of error = E = t/2,df
* (s /
n)
= 2.624 * (10 /
15)
= 6.8
The 98% confidence interval estimate of the population mean is,
- E <
<
+ E
112 - 6.8 <
< 112 + 6.8
105.2 <
< 118.8
The confidence interval is (105.2 , 118.8)