Question

In: Statistics and Probability

A management consultant took a simple random sample of 10 government employees and another simple random...

A management consultant took a simple random sample of 10 government employees and another simple random sample of 10 private sector workers and measured the amount of time (in minutes) they spent in coffee breaks during the day. The results were as follows:

Government Employees

Private Sector Workers

23

25

18

19

34

18

31

22

28

28

33

25

25

21

27

21

32

20

21

16

Does that data provide sufficient evidence to conclude that government employees take longer coffee breaks on average? Use the p-value method with α = 0.05.

(Round answers to 4 decimal places if necessary)

Test statistic =  

P-value =  

Reject null hypothesis?  

Solutions

Expert Solution

Run t-Test: Two-Sample Assuming Equal Variances in excel followed by below procedures.

1. Go to data tab --> data analysis --> choose t-Test: Two-Sample Assuming Equal Variances

Test statistic = 2.7664

P-value = 0.0127

Reject null hypothesis?  

If the p-value is less than 0.05, we reject the null hypothesis that there's no difference between the means and conclude that a significant difference does exist


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