In: Statistics and Probability
Gender |
Yes |
No |
Total |
Female |
625 |
541 |
1166 |
Male |
685 |
510 |
1195 |
Total |
1310 |
1051 |
2361 |
Suppose a person is chosen at random from this sample. Show your work by giving the fraction (using the numbers in the table above). Either round your answers to 4 decimal places or give the fraction reduced to lowest terms.
a) P(female) = 1166 / 2361 = 0.4939
b) P(offended) = 1310 / 2361 = 0.5548
c) P(offended | female) = 625 / 1166 = 0.5360
d) P(male | not offended) = 510 / 1051 = 0.4853
e) P(offended | male) = 685 / 1195 = 0.5732
They are not independent events, because P(offended | male) ≠ P(offended)
f) P(offended and female) = 625 / 2361 = 0.2647
g) P(offended or female) = P(offended) + P(female) - P(offended and female)
= 1310/2361 + 1166/2361 - 625/2361
= 0.7840
h) No, they are not mutually exclusive events. Because P(offended and female) ≠ 0