1.810 g chlorine in methanol is added to 2.200 g of zinc metal. After the reaction...

1.810 g chlorine in methanol is added to 2.200 g of zinc metal. After the reaction is complete, the remaining unreacted zinc was weighed as 0.5260 g. Using the masses of the reacted zinc and chlorine, calculate the empirical formula of zinc chloride.

Expert Solution

Mass of Zn reacted = 2.200 - 0.5260 = 1.674 g.

element mass moles simplest ratio

Zn 1.674 1.674/65 = 0.0258 0.0258/0.0258 = 1

Cl 1.810 1.810 / 35.5 = 0.0510 0.0510 / 0.0258 = 2 (approx.)

Therefore, emperical formula of zinc chloride = ZnCl2

queen_honey_blossom answered 2 years ago

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