In: Chemistry
Cumene, a hydrocarbon, is 89.94% carbon, and its molar mass is 120.2 g/mol.
What are the
a) empirical and b) molecular formulas for Cumene? Show your work
C% = 89.94%
H% = 100-C%
= 100-89.94
= 10.06%
Element % A.Wt Relative numer simple ratio simplest ratio
C 89.94 12 89.94/12 = 7.495 7.495/7.495 = 1 1*3 = 3
H 10.06 1 10.06 /1 = 10.06 10.06/7.495 = 1.342 1.342*3 = 4
The empirical formula = C3H4
Empirical formula mass = 40g/mole
molar mass = 120.2 g/mol.
molecular formula = (empirical formula)n
n = molar mass/empirical formula mass
= 120.2/40 = 3
molecular formula = (C3H4)3 = C9H12