Question

(1A) The mass of Jupiter is 1.898 * 1027kg, and the radius of Jupiter is 69,911 km.

The mass of the sun is 1.989 * 1030, and the radius of the sun is 695,500 km.

What is the weight in Newtons of a 90 kg man at the surface of Jupiter (assuming he had a way to stand there)?

(1B) The mass of Jupiter is 1.898 * 1027kg, and the radius of Jupiter is 69,911 km.

The mass of the sun is 1.989 * 1030, and the radius of the sun is 695,500 km.

What is the gravitational acceleration at the surface of Jupiter?

(1C) The mass of Jupiter is 1.898 * 1027kg, and the radius of Jupiter is 69,911 km.

The mass of the sun is 1.989 * 1030, and the radius of the sun is 695,500 km.

How does the gravitational acceleration at the surface of Jupiter compare to the gravitational acceleration due to Earth at the surface of the earth (i.e., what value is gJupiter at surface / gEarth at surface)?

(1D) The mass of Jupiter is 1.898 * 1027kg, and the radius of Jupiter is 69,911 km. The mass of the sun is 1.989 * 1030, and the radius of the sun is 695,500 km.

What is the weight in Newtons of a 90 kg man at the surface of the sun (assuming he had a way to stand there)?

(1E) The mass of Jupiter is 1.898 * 1027kg, and the radius of Jupiter is 69,911 km. The mass of the sun is 1.989 * 1030, and the radius of the sun is 695,500 km.

What is the gravitational acceleration at the surface of the sun?

(1F) The mass of Jupiter is 1.898 * 1027kg, and the radius of Jupiter is 69,911 km. The mass of the sun is 1.989 * 1030, and the radius of the sun is 695,500 km.

How does the gravitational acceleration at the surface of the sun compare to the gravitational acceleration due to Earth at the surface of the earth (i.e., what value is gSun at surface / gEarth at surface)?

(2A) The mass of Earth is 5.972 * 1024 kg, and the radius of Earth is 6,371 km. What is the gravitational acceleration due to Earth at the surface of Earth?

(2B) The mass of Earth is 5.972 * 1024 kg, and the radius of Earth is 6,371 km. What is the gravitational acceleration due to Earth 3,000 km above the surface of Earth?

(2C) The mass of Earth is 5.972 * 1024 kg, and the radius of Earth is 6,371 km. What is the gravitational acceleration due to Earth 30,000 km above the surface of Earth?

(2D) The mass of Earth is 5.972 * 1024 kg, and the radius of Earth is 6,371 km. How does the gravitational acceleration due to Earth 30,000 km above the surface of Earth compare to the gravitational acceleration due to Earth at the surface of Earth (i.e., what value is gEarth 30,000 km above surface / gEarth at surface)?

(3A) The mass of Earth is 5.972 * 1024 kg, and the radius of Earth is 6,371 km. The mass of the moon is 7.348 * 1022 kg, and the radius of the moon is 1,737 km. The centers of the Earth and the moon are separated by 384,400 km. What is the gravitational acceleration due to the moon at the surface of Earth?

(3C) The mass of Earth is 5.972 * 1024 kg, and the radius of Earth is 6,371 km. The mass of the moon is 7.348 * 1022 kg, and the radius of the moon is 1,737 km. The centers of the Earth and the moon are separated by 384,400 km. What is the gravitational acceleration due to the moon at the surface of the moon?

(3D) The mass of Earth is 5.972 * 1024 kg, and the radius of Earth is 6,371 km. The mass of the moon is 7.348 * 1022 kg, and the radius of the moon is 1,737 km. The centers of the Earth and the moon are separated by 384,400 km. What is the gravitational acceleration due to Earth at the surface of the moon?

(3E) The mass of Earth is 5.972 * 1024 kg, and the radius of Earth is 6,371 km. The mass of the moon is 7.348 * 1022 kg, and the radius of the moon is 1,737 km. The centers of the Earth and the moon are separated by 384,400 km. How does the gravitational acceleration due to Earth at the surface of the moon compare to the gravitational acceleration due to the moon at the surface of the moon (i.e., what value is gEarth at surface of moon / gmoon at surface of moon)?

(4A) The mass of Earth is 5.972 * 1024 kg, and the radius of Earth is 6,371 km. The mass of the moon is 7.348 * 1022 kg, and the radius of the moon is 1,737 km. The centers of the Earth and the moon are separated by 384,400 km. If an object is traveling from Earth to the moon along the line connecting the center of Earth and the center of the moon, at what distance from the center of Earth will the net force on the object due to the gravitational attractions of Earth and the moon be zero?

Answer 1

FIRST FOUR SUB-PARTS AS PER THE RULES...........PLEASE ABIDE BY THE RULES

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(1A)

we find the value of 'g' at the surface of Jupiter

g = GM / r²

where M is mass of jupiter and r is radius

g = 6.67e-11 * 1.898e27 / 69911000²

g = 25.9 m/s²

so,

weight of 90 kg person on Jupiter

W = mg

W = 90 * 25.9

W = 2332 N

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(1B)

g =  GM / r²  

where M is mass of jupiter and r is radius

g = 6.67e-11 * 1.898e27 / 69911000²

g = 25.9 m/s²

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(1C)

g_{Jupiter at surface} / g_{Earth at surface} = 25.9 / 9.8

g_{Jupiter at surface} / g_{Earth at surface} = 2.64

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(1D)

Now, we need to find 'g' for sun

g = GM / r²  

g = 6.67e-11 * 1.989e30 / 695500000²

g = 274.26 m/s²

so,

W = mg

W = 24684 N

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(1E)

g = GM / r²​​​​​​​  

g = 6.67e-11 * 1.989e30 / 695500000²

g = 274.26 m/s²

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(1F)

g_{Sun at surface} / g_{Earth at surface} = 274.26 / 9.81

g_{Sun at surface} / g_{Earth at surface} = 27.95

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(2A)

g =  GM / r²​​​​​​​  

g = 6.67e-11 *5.972e24 / 6371000²

g = 9.81 m/s²

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(2B)

at h = 3000 km above surface

g = 6.67e-11 *5.972e24 / (6371000 + 3000,000)²

g = 4.53 m/s²

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(2C)

at h = 30,000 km

g = 0.3 m/s²

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(2D)

g_{Earth 30,000 km above surface} / g_{Earth at surface} = 0.3 / 9.81

g_{Earth 30,000 km above surface} / g_{Earth at surface} = 0.0306