Question

Question:

I2 is considerably more soluble in CCl4(l) than it is in H2O(l). At a certain temperature, the concentration of I2 in its saturated aqueous solution is 1.300×10−3 M, and the equilibrium achieved when I2 distributes itself between H2Oand CCl4 is

I2(aq)⇌I2(CCl4),K=85.5

Part A

A 14.0-mL sample of saturated I2(aq) is shaken with 14.0 mL of CCl4. After equilibrium is established, the two liquid layers are separated. How many milligrams of I2 will be in the aqueous layer?

Part B

If the 14.0-mL sample of aqueous layer from Part A is extracted with a second 14.0-mL portion of CCl4, how many milligrams of I2 will remain in the aqueous layer when equilibrium is reestablished?

Part C

If the 14.0-mL sample of saturated I2(aq) in Part A had originally been extracted with 28.0 mL of CCl4, how many milligrams of I2 will remain in the aqueous layer when equilibrium is reestablished?

I didn't understand the work of previous Chegg answers for this question, so if someone could clearly explain and show the steps for the math in these three parts, I would really appreciate it. Thank you!

Answer 1