In: Chemistry
Which salts will be more soluble in an acidic solution than in pure water?
PbI2
AIPO4
Zn(OH)2
RbClO4
SrSO4
The ionization and subsequent disolution of salts is as,
Options rulled:
For AlPO4, RbClO4, SrSO4 salts
AIPO4 (aq) Al3+ (aq) + PO43- (aq)
In acidic medium,
Al3+ (aq) + PO43- (aq) + 3H+ (aq) Al3+ (aq) + H3PO4(aq)
H3PO4(aq) is strong acid an eventully ionizes back to PO43- (aq) hence option is rulled out.
3. RbClO4 Rb+ (aq) + ClO4- (aq)
Rb+ (aq) + ClO4- (aq) + H+ (aq) Rb+ (aq) + HClO4(aq)
In acidic medium it gives HClO4 which is strong acid and eventually gives ClO4- back hence ruled out.
SrSO4 Sr2+ (aq) + SO42- (aq)
in acidc medium,
Sr2+ (aq) + SO42- (aq) + 2H+ (aq) Sr2+ (aq) + H2SO4 (aq)
H2SO4 is againn strong acid and eventually gies SO42- ions back for recombination hence rulled out.
2)
PbI2 (aq) Pb2+ (aq) + 2 I- (aq)
Pb2+ (aq) + 2 I- (aq) + 2 H+ Pb2+ (aq) + 2 HI (aq)
HI is weak acid hence obviously in acidic medium solubility of PbI2 will be more.
But in Zn(OH)2 case
Zn(OH)2 (aq) Zn2+ (aq) + 2 HO- (aq)
In acidic medium
Zn2+ (aq) + 2 HO- (aq) + 2 H+ (aq) Zn2+ (aq) + H2O (aq)
H2O is far weak electrolyte than HI and hence almost once formed will not give back HO-.
This sets Zn2+ ions freely dissolved state and hence the solubility.
Answer: Zn(OH)2 in acidic medium will be most soluble salt.
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