Question

Stock solutions will be available which are 0.23 M cyclohexanone, 0.5 M H+, and 0.018 M I3–. Mixture B: 1.0 mL H+ (acid) 1.5 mL cyclohexanone For measuring the order with respect to cyclohexanone: Mixture C: .5 mL H+ (acid) 1.0 mL cyclohexanone 1.0 mL distilled water Mixture D: 0.5 mL H+ (acid) 2 mL cyclohexanone You will then add 0.5 mL of I3– solution to each of these mixtures to start the reaction. The total volume of each mixture after the I3– is added will be 3.0 mL. Using this information, determine the initial concentrations of H+, cyclohexanone, and I3– at the start of the reaction for each of these mixtures.

Answer 1

Using the above relationship we will calculate the initial concentration M_H⁺, M_{cyclohexanone} , M_I3

mixture B: 1 mL x 0.5 M = M_H⁺ x 3 mL, M_H⁺ = 0.167 M

                 1.5 mL x 0.23 M = M_{cyclohexanone} x 3 mL, M_{cyclohexanone} = 0.115 M

                 0.5 mL x 0.018 M = M_I3 x 3 mL , M_I3 = 0.003 M

mixture C: 5 mL x 0.5 M = M_H⁺ x 3 mL, M_H⁺ = 0.833 M

                 0.1 mL x 0.23 M = M_{cyclohexanone} x 3 mL, M_{cyclohexanone} = 0.0077 M

                 0.5 mL x 0.018 M = M_I3 x 3 mL , M_I3 = 0.003 M

mixture D: 0.5 mL x 0.5 M = M_H⁺ x 3 mL, M_H⁺ = 0.083M

                 2 mL x 0.23 M = M_{cyclohexanone} x 3 mL, M_{cyclohexanone} = 0.153 M

                 0.5 mL x 0.018 M = M_I3 x 3 mL , M_I3 = 0.003 M