In: Statistics and Probability
Let x be an exponential random variable with lambda equals 0.2. Calculate the probabilities described below.
a. P(x<7)
b. P(x>8)
c. P(7< = x < = 8)
d. P(x> = 6)
e. the probability that x is at most 8
This Problem is solved by using R
X ~ Exponential( lambda=0.2)
X is continuous distribution so at a certain point probability
equal to zero therefore P(X<x)=P(X<=x)
Answer :
a. P(x<7) = 0.753403
b. P(x>8)=0.2018965
c. P(7< = x < = 8) =0.04470045
d. P(x> = 6) =0.3011942
e. the probability that x is at most 8 =P(x<=8) = 0.7981035
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