(a) A light, rigid rod of length ℓ = 1.00 m joins two particles, with masses m = 4.00 kg and m, = 3.00 kg, at its ends. The combination rotates in the xy-plane about a pivot through the center of the rod (see figure below). Determine the angular momentum of the system about the origin when the speed of each particle is 7.60 m/s. (Enter the magnitude to at least two decimal places in kg. m2/s.) <img src="//img.wizedu.com/questions/9482d680-a5d1-11ec-ab0e-01e4a1c6d5fd.png" title="1647507923207556.png" alt="image.png" />(b) What If? What would be the new angular momentum of the system (in kg. m2/s) if each of the masses were instead a solid sphere 13.0 cm in diameter? (Round your answer to at least two decimal places.)

Question

In: Physics

A light, rigid rod of length ℓ = 1.00 m joins two particles, with masses...

(a) A light, rigid rod of length ℓ = 1.00 m joins two particles, with masses m = 4.00 kg and m, = 3.00 kg, at its ends. The combination rotates in the xy-plane about a pivot through the center of the rod (see figure below). Determine the angular momentum of the system about the origin when the speed of each particle is 7.60 m/s. (Enter the magnitude to at least two decimal places in kg. m²/s.)

(b) What If? What would be the new angular momentum of the system (in kg. m²/s) if each of the masses were instead a solid sphere 13.0 cm in diameter? (Round your answer to at least two decimal places.)

Solutions

Expert Solution

genius_generous answered 2 years ago

Next > < Previous

Related Solutions

(a) A light, rigid rod of length 1.00 m joins two particles, with masses m-4.00 kg...

(a) A light, rigid rod of length 1.00 m joins two particles, with masses m1 = 4.00 kg and m2 = 3.00 kg, at its ends. The combination rotates in the xy-plane about a pivot through the center of the rod (see figure below . Determine the angular momentum of the system about the origin when the speed of each particle is 4.40 m/s. (Enter the magnitude to at least two decimal places in kg·m2/s. (b) What I? What would be...

A pendulum consists of a light rigid rod of length 250 mm, with two identical uniform...

A pendulum consists of a light rigid rod of length 250 mm, with two identical uniform solid spheres of radius 50 mm attached one on either side of its lower end. Find the period of small oscillations (a) perpendicular to the line of centers and (b) along it.

The masses and coordinates of three particles are as follows: 20.0 kg, (0.50, 1.00) m; 361.0...

The masses and coordinates of three particles are as follows: 20.0 kg, (0.50, 1.00) m; 361.0 kg, (-1.00, -1.00) m; 54.0 kg, (0.00, -0.50) m. What is the gravitational force on a 20.0 kg sphere located at the origin due to the other spheres, magnitude and direction? Give the direction as an angle in degrees counter clockwise with respect to the the + x-axis.

Let's consider a rigid system with three particles. Masses of these particles m1 = 3 kgs,...

Let's consider a rigid system with three particles. Masses of these particles m1 = 3 kgs, m2 = 4 kg, m3 = 2 kgs, and their positions are (1, 0, 1), (1, 1, -1) and Let it be (1, -1, 0). Locations are given in meters. a) What is the inertia tensor of the system? b) What are the main moments of inertia? c) What are the main axes? THERE IS NO MORE INFORMATION AND PICTURE FOR THIS QUESTION, TY...

Two uniform solid spheres are joined by a light rigid rod to form a dumbbell. The...

Two uniform solid spheres are joined by a light rigid rod to form a dumbbell. The spheres are identical, and each has mass M/2. One end of a spring is attached to the center of the rod, the spring is stretched perpendicular to the rod, and the other end of the spring is attached to a wall. The dumbbell rests on a horizontal surface. Friction between the surface and the spheres prevents slipping. The system is released from rest. a)...

A 3.1 kg rod of length 5.1 m has at opposite ends point masses of 4.0...

A 3.1 kg rod of length 5.1 m has at opposite ends point masses of 4.0 kg and 6.0 kg. a)Will the center of mass of this system be nearer to the 4.0-kg mass, nearer to the 6.0-kgmass, or at the center of the rod? b) Where is the center of mass of the system? (F-net=M[Vcm/t] xCM= (summation of all mass by distance)/system of mass Diagram please, not fully understand the system. getting 5.03m

1. A rod of uniform density and weight W=120N has length L=1.00 m and is supported...

1. A rod of uniform density and weight W=120N has length L=1.00 m and is supported at two points, under the 10 cm point and under the 70 cm point. The support at 10 cm exerts a force NL on the rod and the support at 70 cm exerts a force NR on the rod, both forces being in the vertical direction. (a) Use the conditions of static equilibrium to find the values of NL and NR. (b) In order...

Two blocks of masses m and 3m are placed on a frictionless, horizontal surface. A light...

Two blocks of masses m and 3m are placed on a frictionless, horizontal surface. A light spring is attached to the more massive block, and the blocks are pushed together with the spring between them as shown in the figure below. A cord initially holding the blocks together is burned; after that happens, the block of mass 3m moves to the right with a speed of v with arrow3m = 1.70 m/s. (a) What is the velocity of the block...

One end of a uniform ℓ = 4.40-m-long rod of weight w issupported by a...

One end of a uniform ℓ = 4.40-m-long rod of weight w is supported by a cable at an angle ofθ = 37°with the rod. The other end rests against a wall, where it is held by friction (see figure). The coefficient of static friction between the wall and the rod isμs = 0.595.Determine the minimum distance x from point Aat which an additional weight w (the same as the weight of the rod) can be hung without causing the...

A thin, cylindrical rod ℓ = 27.0 cm long with a mass m = 1.20 kg...

A thin, cylindrical rod ℓ = 27.0 cm long with a mass m = 1.20 kg has a ball of diameter d = 10.00 cm and mass M = 2.00 kg attached to one end. The arrangement is originally vertical and stationary, with the ball at the top as shown in the figure below. The combination is free to pivot about the bottom end of the rod after being given a slight nudge. (a) After the combination rotates through 90...

Subjects