In: Chemistry
A 147-g sample of steam at 100 ∘C is emitted from a volcano. It condenses, cools, and falls as snow at 0 ∘C. (For water, 80. cal (334 J) is needed to melt 1 g of ice or must be removed to freeze 1 g of water and 540 cal (2260 J) is needed to convert 1 g of water to vapor at 100 ∘C.) Part A How many kilojoules of heat were released?
Answer – We are given, mass of sample steam = 147 g , ti = 100oC, tf = 0.0oC
∆Hfus = 334 J/g , ∆Hvap = 2260 J/g
We know
Heat from the 100oC to 100oC
q1 = m*∆H vap
= 147.0 g * 2260 J/g
= - 332220 J
Heat from the 100.0oC to 0.0oC
q2 = m*C liq* ∆t
= 147.0 g * 4.184 J/goC * (0.0oC –100.0oC)
= - 61505 J
Heat from 0.0oC to 0.00oC
q3 = m*∆H fus
= 147.0 g * 334 J/g
= - 49098 J
Total heat q = q1+ q2+q3
= -332220 J -61505 J - 49098
= 442823 J
= 442.8 kJ
So, - 442.8 kJ heat were released