In: Statistics and Probability
The following data represent the high-temperature distribution for a summer month in a city for some of the last 130 years. Treat the data as a population. Complete parts (a) through (c).
Temperature : 50-59 60-69 70-79 80-89 90-99 100-109
Days: 5 303 1450 1516 438 8
(a) Approximate the mean and standard deviation for temperature.
Mean = __________ (Round to one decimal place as needed.)
Standard Deviation = ___________ (Round to one decimal place as needed.)
(b) Use the frequency histogram of the data to verify that the distribution is bell shaped.
___ Yes, the frequency histogram of the data is bell shaped.
___ No, the frequency histogram of the data is not bell shaped.
(c) According to the empirical rule, 95% of days in the month will be between what two temperatures?
_____ and _____ (Round to one decimal place as needed. Use ascending order.)
x |
f | f*M | f*M2 |
54.5 | 5 | 272.5 | 14851.25 |
64.5 | 303 | 19543.5 | 1260555.75 |
74.5 | 1450 | 108025 | 8047862.5 |
84.5 | 1516 | 128102 | 10824619 |
94.5 | 438 | 41391 | 3911449.5 |
104.5 | 8 | 836 | 87362 |
total | 3720 | 298170 | 24146700 |
mean =x̅=Σf*M/Σf= | 80.1532 | ||
Variance σ2=(ΣfM2-(ΣfM)2/n)/n= | 66.5087799 | ||
Std deviation σ= | √σ2 = | 8.15529153 |
from above mean =80.2
standard deviation σ=8.2
b) histogram
Yes, the frequency histogram of the data is bell shaped
(c) According to the empirical rule, 95% of days in the month will be between what two temperatures?
95% of days in
-/+ 2*σ =(80.2 -2*8.2 , 80.2 + 2*8.2) = (63.8 , 96.6)
95% of days in the month will be between (63.8 , 96.6)
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