In: Statistics and Probability
The following data represent the high-temperature distribution for a summer month in a city for some of the last 130 years. Treat the data as a population.
Temperature 50-59 60-69 70-79 80-89 90-99 100-109
Days 1 305 1469 1523 571 6
a.) Approximate the mean and standard deviation for temperature.
Mean =
Standard Deviation =
b.) Use the frequency histogram of the data to verify that the distribution is bell shaped.
- Yes, the frequency histogram of the data is bell shaped.
- No, the frequency histogram of the data is not bell shaped.
c.) According to the empirical rule, 95% of days in the month will be between what two temperatures?
____ and _____ (Round to one decimal place as needed. Use ascending order)
Temperature | mid point | Days | Xf | (X-xbar)2 | (x-xbar)2 f |
50-59 | 54.5 | 1 | 54.5 | 682.7769 | 682.7769 |
60-69 | 64.5 | 305 | 19672.5 | 260.1769 | 79353.95 |
70-79 | 74.5 | 1469 | 109440.5 | 37.5769 | 55200.47 |
80-89 | 84.5 | 1523 | 128693.5 | 14.9769 | 22809.82 |
90-99 | 94.5 | 571 | 53959.5 | 192.3769 | 109847.2 |
100-109 | 104.5 | 6 | 627 | 569.7769 | 3418.661 |
Total | 3875 | 312447.5 | 271312.9 |
a)
Approximate the mean and standard deviation for temperature.
Mean ;
= 312447.5 / 3875
= 80.63
Standard Deviation ,
= 8.368
b)
ans) Yes, the frequency histogram of the data is bell shaped.
c) According to the empirical rule, 95% of days in the month will be between ,
= 63.89 and 97.37
****If you have any queries or doubts please comment below, if you're satisfied please give a like. Thank you!