Suppose 0.2 moles of an ideal diatomic gas (Cv = 20.8 J/mol·K) undergoes a Carnot cycle...

Suppose 0.2 moles of an ideal diatomic gas (Cv = 20.8 J/mol·K) undergoes a Carnot cycle between temperatures of 227˚C and 27˚C. The initial volume of the gas is 8.31×10-4 m3 and during the high temperature isothermal expansion, the volume doubles.

a) Find the work done during the entire cycle

b) Find the efficiency of the cycle

Expert Solution

WCD = nRTc*ln(VD / VC) = -345.76

WDA = -nCvdT = -831.4 J

Total work done,

W = 576.28 + 831.4 - 345.78 - 831.4

W = 230.7 J

(b)

Effiecienc of carnot cycle,

e = (Th - Tc)*100 / Th

e = (500 - 300)*100 / 500

e = 40 %

genius_generous answered 2 years ago

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