In: Chemistry
Calculate the pH of a buffer solution prepared by mixing 20 mL of 5.0% acetic acid with 20 mL of 0.50 M NaOH and 100 mL of water
5% acetic acid molarity = 0.833 M
millimoles of acetic acid = 0.833 x 20 = 16.66
NaOH millimoles = 0.50 x 20 = 10
CH3COOH + NaOH -----------------------------> CH3COONa + H2O
16.66 10 0 0 --------------> initial
6.66 0 10 10 ----------------> after reaction
pKa of acetic acid = 4.74
pH = pKa + log [CH3COONa]/[CH3COOH]
pH = 4.74 + log (10 / 6.66)
pH = 4.92