A.The area of the primary coil (the current source) is 3*10^-4 m^2. The period for the...

A.The area of the primary coil (the current source) is 3*10^-4 m^2. The period for the

AC power current oscillation is 1.6*10^-2 seconds, thus, the voltage goes from zero to

the root mean square voltage in 0.4*10^-2 seconds. Calculate the root mean square

voltage of the AC power supply

B.What is the root mean square voltage for the secondary coil (pickup coil) if there is one

loop for the primary coil (current source coil) and one loop for the secondary coil

(pickup coil)?

C. What is the root mean square voltage for the secondary coil (pickup coil) if there is one

loop for the primary coil (current source coil) and four loops for the secondary coil

(pickup coil)?

D. How will changing the area of the loops for the secondary coil (pickup coil) affect the

calculations that you completed in parts b and c? Provide your response in terms of

magnetic flux

Solutions

Expert Solution

genius_generous answered 1 year ago

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