In: Chemistry
A 0.7221g sample of a new compound has been analyze
and found to contain the following masses of elements : Carbon
0.2990g, hydrogen 0.05489g, nitrogen 0.2318g, and Oxygen
0.1328g.
call ate the empirical formula of the compound
Carbon = 0.2990g = 0.2990g / (12g/mol) = 0.025 mol,
Hydrogen = 0.05489g = 0.05489g / (1.0 g/mol) = 0.05489 mol
nitrogen = 0.2318g = 0.2318g/ (14.0 g/mol) = 0.0166 mol ,
Aand Oxygen 0.1328g = 0.1328g/ (16.0 g/mol) = 0.0083 mol.
The molar ratio of = Carbon:hydrogen : nitrogen: Oxygen = 0.025 : 0.05489: 0.0166: 0.0083
= 1 : 2.12 : 0.66 : 0.33
= 3.03 : 6.42 : 2 : 1
So, the empirical formula of the compound is C3H6O2N