How many molecules of NH3 are produced from 8.50x10^-4 g of H2

Expert Solution

no of moles of H2 = W/G.A.Wt

= 8.5*10^-4/2 = 4.25*10^-4

N2 + 3H2 ----------------> 2NH3

3 moles of H2 react with N2 to from 2 moles of NH3

4.25*10^-4 moles of H2 react with N2 to form =2*4.25*10^-4/3

= 2.83*10^-4 moles of NH3

no of molecules = no of moles* 6.023*10²³

= 2.83*10^-4 * 6.023*10²³

= 1.704*10²⁰ molecules

queen_honey_blossom answered 1 year ago

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