Take the Laplace transform of the following initial value and
solve for Y(s)=L{y(t)}: y′′+4y={sin(πt) ,0, 0≤t<11≤t
y(0)=0,y′(0)=0
Y(s)= ? Hint: write the right hand side in
terms of the Heaviside function. Now find the inverse transform to
find y(t). Use step(t-c) for the Heaviside function u(t−c) .
y(t)= ?
Solve for Y(s), the Laplace transform of the solution y(t) to
the initial value problem below. y'''+7y''+4y'-12y= -24, y(0) = 11,
y'(0)= 5, y''(0) = -43
Take the Laplace transform of the following initial value and
solve for X(s)=L{x(t)}X(s)=L{x(t)}:
x′′+16x={sin(πt),0}
0≤t<1
1≤t
x(0)=0
x′(0)=0.
a) X(s)=
Now find the inverse transform to find
b) x(t)=
Use u(t−a) for the Heaviside function shifted a units
horizontaly.